Base | Representation |
---|---|
bin | 10100011110011001000… |
… | …001101101111110111011 |
3 | 11222111202202111121100222 |
4 | 110132121001231332323 |
5 | 141023040021422311 |
6 | 2554213221250255 |
7 | 203440210603064 |
oct | 24363101557673 |
9 | 4874682447328 |
10 | 1407021670331 |
11 | 4a2795063122 |
12 | 1a883486398b |
13 | a28b25595a4 |
14 | 4c158da756b |
15 | 268ee809adb |
hex | 1479906dfbb |
1407021670331 has 2 divisors, whose sum is σ = 1407021670332. Its totient is φ = 1407021670330.
The previous prime is 1407021670303. The next prime is 1407021670333. The reversal of 1407021670331 is 1330761207041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1407021670331 - 210 = 1407021669307 is a prime.
It is a super-2 number, since 2×14070216703312 (a number of 25 digits) contains 22 as substring.
Together with 1407021670333, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1407021670291 and 1407021670300.
It is not a weakly prime, because it can be changed into another prime (1407021670333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 703510835165 + 703510835166.
It is an arithmetic number, because the mean of its divisors is an integer number (703510835166).
Almost surely, 21407021670331 is an apocalyptic number.
1407021670331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1407021670331 is an equidigital number, since it uses as much as digits as its factorization.
1407021670331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21168, while the sum is 35.
Adding to 1407021670331 its reverse (1330761207041), we get a palindrome (2737782877372).
The spelling of 1407021670331 in words is "one trillion, four hundred seven billion, twenty-one million, six hundred seventy thousand, three hundred thirty-one".
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