14095489324117 has 2 divisors, whose sum is σ = 14095489324118. Its totient is φ = 14095489324116.

The previous prime is 14095489324051. The next prime is 14095489324141. The reversal of 14095489324117 is 71142398459041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13829763507921 + 265725816196 = 3718839^2 + 515486^2 .

It is a cyclic number.

It is not a de Polignac number, because 14095489324117 - 2¹¹ = 14095489322069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14095489324157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7047744662058 + 7047744662059.

It is an arithmetic number, because the mean of its divisors is an integer number (7047744662059).

Almost surely, 2^{14095489324117} is an apocalyptic number.

It is an amenable number.

14095489324117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14095489324117 is an equidigital number, since it uses as much as digits as its factorization.

14095489324117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8709120, while the sum is 58.

The spelling of 14095489324117 in words is "fourteen trillion, ninety-five billion, four hundred eighty-nine million, three hundred twenty-four thousand, one hundred seventeen".