Base | Representation |
---|---|
bin | 11010010000101100… |
… | …10100100001001011 |
3 | 1100101120012210212122 |
4 | 31020112110201023 |
5 | 212333232301101 |
6 | 10251000201455 |
7 | 1006244036342 |
oct | 151026244113 |
9 | 40346183778 |
10 | 14098712651 |
11 | 5a853a0541 |
12 | 289576928b |
13 | 1438bc172a |
14 | 97a650b59 |
15 | 577b3151b |
hex | 34859484b |
14098712651 has 2 divisors, whose sum is σ = 14098712652. Its totient is φ = 14098712650.
The previous prime is 14098712627. The next prime is 14098712653. The reversal of 14098712651 is 15621789041.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14098712651 is a prime.
Together with 14098712653, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14098712653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7049356325 + 7049356326.
It is an arithmetic number, because the mean of its divisors is an integer number (7049356326).
Almost surely, 214098712651 is an apocalyptic number.
14098712651 is a deficient number, since it is larger than the sum of its proper divisors (1).
14098712651 is an equidigital number, since it uses as much as digits as its factorization.
14098712651 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120960, while the sum is 44.
The spelling of 14098712651 in words is "fourteen billion, ninety-eight million, seven hundred twelve thousand, six hundred fifty-one".
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