14100054050501 has 2 divisors, whose sum is σ = 14100054050502. Its totient is φ = 14100054050500.

The previous prime is 14100054050491. The next prime is 14100054050543. The reversal of 14100054050501 is 10505045000141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9135294676225 + 4964759374276 = 3022465^2 + 2228174^2 .

It is a cyclic number.

It is not a de Polignac number, because 14100054050501 - 2⁶ = 14100054050437 is a prime.

It is a super-3 number, since 3×14100054050501³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14100054059501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050027025250 + 7050027025251.

It is an arithmetic number, because the mean of its divisors is an integer number (7050027025251).

Almost surely, 2^{14100054050501} is an apocalyptic number.

It is an amenable number.

14100054050501 is a deficient number, since it is larger than the sum of its proper divisors (1).

14100054050501 is an equidigital number, since it uses as much as digits as its factorization.

14100054050501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2000, while the sum is 26.

Adding to 14100054050501 its reverse (10505045000141), we get a palindrome (24605099050642).

The spelling of 14100054050501 in words is "fourteen trillion, one hundred billion, fifty-four million, fifty thousand, five hundred one".