141001212321311 has 2 divisors, whose sum is σ = 141001212321312. Its totient is φ = 141001212321310.

The previous prime is 141001212321293. The next prime is 141001212321371. The reversal of 141001212321311 is 113123212100141.

141001212321311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (113123212100141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141001212321311 is a prime.

It is a super-2 number, since 2×141001212321311² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141001212321371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70500606160655 + 70500606160656.

It is an arithmetic number, because the mean of its divisors is an integer number (70500606160656).

Almost surely, 2^{141001212321311} is an apocalyptic number.

141001212321311 is a deficient number, since it is larger than the sum of its proper divisors (1).

141001212321311 is an equidigital number, since it uses as much as digits as its factorization.

141001212321311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 141001212321311 its reverse (113123212100141), we get a palindrome (254124424421452).

The spelling of 141001212321311 in words is "one hundred forty-one trillion, one billion, two hundred twelve million, three hundred twenty-one thousand, three hundred eleven".