1410014300111 has 2 divisors, whose sum is σ = 1410014300112. Its totient is φ = 1410014300110.

The previous prime is 1410014300083. The next prime is 1410014300117. The reversal of 1410014300111 is 1110034100141.

It is a strong prime.

It is an emirp because it is prime and its reverse (1110034100141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1410014300111 is a prime.

It is a super-2 number, since 2×1410014300111² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1410014300111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1410014300117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705007150055 + 705007150056.

It is an arithmetic number, because the mean of its divisors is an integer number (705007150056).

Almost surely, 2^{1410014300111} is an apocalyptic number.

1410014300111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1410014300111 is an equidigital number, since it uses as much as digits as its factorization.

1410014300111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1410014300111 its reverse (1110034100141), we get a palindrome (2520048400252).

The spelling of 1410014300111 in words is "one trillion, four hundred ten billion, fourteen million, three hundred thousand, one hundred eleven".