Base | Representation |
---|---|
bin | 100000000011110111011001… |
… | …101111001111011110010000 |
3 | 200111020202201212121000002221 |
4 | 200003313121233033132100 |
5 | 121440143404401303100 |
6 | 1215515540134350424 |
7 | 41462066055016516 |
oct | 4003673157173620 |
9 | 614222655530087 |
10 | 141003134400400 |
11 | 40a23103474598 |
12 | 139934284bb414 |
13 | 608a70018a11c |
14 | 26b6833b244b6 |
15 | 1147c35ee401a |
hex | 803dd9bcf790 |
141003134400400 has 60 divisors (see below), whose sum is σ = 338907769204372. Its totient is φ = 56376656248320.
The previous prime is 141003134400383. The next prime is 141003134400419. The reversal of 141003134400400 is 4004431300141.
It can be written as a sum of positive squares in 6 ways, for example, as 40565536715664 + 100437597684736 = 6369108^2 + 10021856^2 .
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 75948879 + ... + 77783278.
Almost surely, 2141003134400400 is an apocalyptic number.
141003134400400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
141003134400400 is an abundant number, since it is smaller than the sum of its proper divisors (197904634803972).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141003134400400 is a wasteful number, since it uses less digits than its factorization.
141003134400400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 153734468 (or 153734457 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 141003134400400 its reverse (4004431300141), we get a palindrome (145007565700541).
The spelling of 141003134400400 in words is "one hundred forty-one trillion, three billion, one hundred thirty-four million, four hundred thousand, four hundred".
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