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14100541224251 is a prime number
BaseRepresentation
bin1100110100110000100111…
…0000000011010100111011
31211220222221221222100002212
43031030021300003110323
53322010402023134001
645553411010245335
72653505361560246
oct315141160032473
954828857870085
1014100541224251
114547007a14559
1216b894288684b
137b38a1920611
1436a68133625d
15196bc28e57bb
hexcd309c0353b

14100541224251 has 2 divisors, whose sum is σ = 14100541224252. Its totient is φ = 14100541224250.

The previous prime is 14100541224247. The next prime is 14100541224269. The reversal of 14100541224251 is 15242214500141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14100541224251 - 22 = 14100541224247 is a prime.

It is a super-2 number, since 2×141005412242512 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14100541224281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050270612125 + 7050270612126.

It is an arithmetic number, because the mean of its divisors is an integer number (7050270612126).

Almost surely, 214100541224251 is an apocalyptic number.

14100541224251 is a deficient number, since it is larger than the sum of its proper divisors (1).

14100541224251 is an equidigital number, since it uses as much as digits as its factorization.

14100541224251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12800, while the sum is 32.

Adding to 14100541224251 its reverse (15242214500141), we get a palindrome (29342755724392).

The spelling of 14100541224251 in words is "fourteen trillion, one hundred billion, five hundred forty-one million, two hundred twenty-four thousand, two hundred fifty-one".