Base | Representation |
---|---|
bin | 100000000011111101110101… |
… | …100110011111100101101111 |
3 | 200111021102120102211021222012 |
4 | 200003331311212133211233 |
5 | 121440302032321220421 |
6 | 1215523041534111435 |
7 | 41462432231250161 |
oct | 4003756546374557 |
9 | 614242512737865 |
10 | 141010044320111 |
11 | 40a2602999253a |
12 | 1399483664b57b |
13 | 608b261913705 |
14 | 26b6ccb712931 |
15 | 1147edc96795b |
hex | 803f7599f96f |
141010044320111 has 2 divisors, whose sum is σ = 141010044320112. Its totient is φ = 141010044320110.
The previous prime is 141010044320087. The next prime is 141010044320219. The reversal of 141010044320111 is 111023440010141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141010044320111 - 214 = 141010044303727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141010044340111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70505022160055 + 70505022160056.
It is an arithmetic number, because the mean of its divisors is an integer number (70505022160056).
Almost surely, 2141010044320111 is an apocalyptic number.
141010044320111 is a deficient number, since it is larger than the sum of its proper divisors (1).
141010044320111 is an equidigital number, since it uses as much as digits as its factorization.
141010044320111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 141010044320111 its reverse (111023440010141), we get a palindrome (252033484330252).
The spelling of 141010044320111 in words is "one hundred forty-one trillion, ten billion, forty-four million, three hundred twenty thousand, one hundred eleven".
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