Base | Representation |
---|---|
bin | 10100100001010000110… |
… | …000010110100001101111 |
3 | 11222210201120200120000010 |
4 | 110201100300112201233 |
5 | 141100343124004201 |
6 | 2555443133104303 |
7 | 203606460206022 |
oct | 24412060264157 |
9 | 4883646616003 |
10 | 1410104125551 |
11 | 4a4027021380 |
12 | 1a9355028093 |
13 | a2c840508a4 |
14 | 4c36c5151b9 |
15 | 26a30239bd6 |
hex | 14850c1686f |
1410104125551 has 32 divisors (see below), whose sum is σ = 2182003819776. Its totient is φ = 800525376000.
The previous prime is 1410104125489. The next prime is 1410104125553. The reversal of 1410104125551 is 1555214010141.
It is not a de Polignac number, because 1410104125551 - 211 = 1410104123503 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1410104125553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5837920 + ... + 6074661.
It is an arithmetic number, because the mean of its divisors is an integer number (68187619368).
Almost surely, 21410104125551 is an apocalyptic number.
1410104125551 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1410104125551 is a deficient number, since it is larger than the sum of its proper divisors (771899694225).
1410104125551 is a wasteful number, since it uses less digits than its factorization.
1410104125551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11912823.
The product of its (nonzero) digits is 4000, while the sum is 30.
Adding to 1410104125551 its reverse (1555214010141), we get a palindrome (2965318135692).
The spelling of 1410104125551 in words is "one trillion, four hundred ten billion, one hundred four million, one hundred twenty-five thousand, five hundred fifty-one".
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