14101053120000 has 1200 divisors, whose sum is σ = 63403965136512. Its totient is φ = 2930042880000.

The previous prime is 14101053119977. The next prime is 14101053120029. The reversal of 14101053120000 is 2135010141.

14101053120000 is a `hidden beast` number, since 1 + 410 + 1 + 0 + 53 + 1 + 200 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1200).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 221728207 + ... + 221791793.

Almost surely, 2^{14101053120000} is an apocalyptic number.

14101053120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14101053120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (31701982568256).

14101053120000 is an abundant number, since it is smaller than the sum of its proper divisors (49302912016512).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14101053120000 is an equidigital number, since it uses as much as digits as its factorization.

14101053120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63649 (or 63615 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 14101053120000 its reverse (2135010141), we get a palindrome (14103188130141).

The spelling of 14101053120000 in words is "fourteen trillion, one hundred one billion, fifty-three million, one hundred twenty thousand".