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14101251345331 is a prime number
BaseRepresentation
bin1100110100110011010000…
…0100111100101110110011
31211221001210110012020002121
43031030310010330232303
53322013330321022311
645554005254455111
72653532103524143
oct315146404745663
954831713166077
1014101251345331
114547341846a87
1216b8b00664497
137b3985a946c7
1436a70b786923
15196c14e16b71
hexcd33413cbb3

14101251345331 has 2 divisors, whose sum is σ = 14101251345332. Its totient is φ = 14101251345330.

The previous prime is 14101251345299. The next prime is 14101251345353. The reversal of 14101251345331 is 13354315210141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14101251345331 - 25 = 14101251345299 is a prime.

It is a super-2 number, since 2×141012513453312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14101251345031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050625672665 + 7050625672666.

It is an arithmetic number, because the mean of its divisors is an integer number (7050625672666).

Almost surely, 214101251345331 is an apocalyptic number.

14101251345331 is a deficient number, since it is larger than the sum of its proper divisors (1).

14101251345331 is an equidigital number, since it uses as much as digits as its factorization.

14101251345331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21600, while the sum is 34.

Adding to 14101251345331 its reverse (13354315210141), we get a palindrome (27455566555472).

The spelling of 14101251345331 in words is "fourteen trillion, one hundred one billion, two hundred fifty-one million, three hundred forty-five thousand, three hundred thirty-one".