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141012673132333 is a prime number
BaseRepresentation
bin100000000100000000010010…
…010010100111011100101101
3200111021200100122101210101211
4200010000102102213130231
5121440322423310213313
61215524154442434421
741462554331631562
oct4004002222473455
9614250318353354
10141012673132333
1140a27158877022
121399524ab02a11
13608b590433ac2
1426b709a8d4869
1511480e3639e3d
hex8040124a772d

141012673132333 has 2 divisors, whose sum is σ = 141012673132334. Its totient is φ = 141012673132332.

The previous prime is 141012673132321. The next prime is 141012673132351. The reversal of 141012673132333 is 333231376210141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99397749504964 + 41614923627369 = 9969842^2 + 6450963^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141012673132333 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141012673132733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70506336566166 + 70506336566167.

It is an arithmetic number, because the mean of its divisors is an integer number (70506336566167).

Almost surely, 2141012673132333 is an apocalyptic number.

It is an amenable number.

141012673132333 is a deficient number, since it is larger than the sum of its proper divisors (1).

141012673132333 is an equidigital number, since it uses as much as digits as its factorization.

141012673132333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 163296, while the sum is 40.

The spelling of 141012673132333 in words is "one hundred forty-one trillion, twelve billion, six hundred seventy-three million, one hundred thirty-two thousand, three hundred thirty-three".