14101555133 has 2 divisors, whose sum is σ = 14101555134. Its totient is φ = 14101555132.

The previous prime is 14101555123. The next prime is 14101555177. The reversal of 14101555133 is 33155510141.

14101555133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9930720409 + 4170834724 = 99653^2 + 64582^2 .

It is a cyclic number.

It is not a de Polignac number, because 14101555133 - 2¹⁰ = 14101554109 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14101555096 and 14101555105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14101555103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050777566 + 7050777567.

It is an arithmetic number, because the mean of its divisors is an integer number (7050777567).

Almost surely, 2^14101555133 is an apocalyptic number.

It is an amenable number.

14101555133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14101555133 is an equidigital number, since it uses as much as digits as its factorization.

14101555133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4500, while the sum is 29.

The spelling of 14101555133 in words is "fourteen billion, one hundred one million, five hundred fifty-five thousand, one hundred thirty-three".