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141020303424 = 263721113372833
BaseRepresentation
bin1000001101010101110…
…1110001000001000000
3111110222221120122220220
42003111131301001000
54302302144202144
6144441150303040
713121420541600
oct2032535610100
9443887518826
10141020303424
1154896315210
12233b74b7a80
13103b508a730
146b7ad42c00
153a055b3919
hex20d5771040

141020303424 has 672 divisors, whose sum is σ = 523879364736. Its totient is φ = 32885637120.

The previous prime is 141020303363. The next prime is 141020303453. The reversal of 141020303424 is 424303020141.

It is a tau number, because it is divible by the number of its divisors (672).

It is a super-2 number, since 2×1410203034242 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a junction number, because it is equal to n+sod(n) for n = 141020303394 and 141020303403.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 49776312 + ... + 49779144.

It is an arithmetic number, because the mean of its divisors is an integer number (779582388).

Almost surely, 2141020303424 is an apocalyptic number.

141020303424 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 141020303424, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (261939682368).

141020303424 is an abundant number, since it is smaller than the sum of its proper divisors (382859061312).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141020303424 is a wasteful number, since it uses less digits than its factorization.

141020303424 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2923 (or 2906 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 141020303424 its reverse (424303020141), we get a palindrome (565323323565).

It can be divided in two parts, 141020 and 303424, that added together give a palindrome (444444).

The spelling of 141020303424 in words is "one hundred forty-one billion, twenty million, three hundred three thousand, four hundred twenty-four".