Base | Representation |
---|---|
bin | 11010010001000110… |
… | …00000110111001011 |
3 | 1100101210110212011012 |
4 | 31020203000313023 |
5 | 212340110240021 |
6 | 10251155354135 |
7 | 1006314235163 |
oct | 151043006713 |
9 | 40353425135 |
10 | 14102040011 |
11 | 5a87263424 |
12 | 28968b294b |
13 | 14397b8097 |
14 | 97ac795a3 |
15 | 57808c35b |
hex | 3488c0dcb |
14102040011 has 2 divisors, whose sum is σ = 14102040012. Its totient is φ = 14102040010.
The previous prime is 14102039957. The next prime is 14102040023. The reversal of 14102040011 is 11004020141.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14102040011 - 214 = 14102023627 is a prime.
It is not a weakly prime, because it can be changed into another prime (14102048011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051020005 + 7051020006.
It is an arithmetic number, because the mean of its divisors is an integer number (7051020006).
Almost surely, 214102040011 is an apocalyptic number.
14102040011 is a deficient number, since it is larger than the sum of its proper divisors (1).
14102040011 is an equidigital number, since it uses as much as digits as its factorization.
14102040011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 14102040011 its reverse (11004020141), we get a palindrome (25106060152).
The spelling of 14102040011 in words is "fourteen billion, one hundred two million, forty thousand, eleven".
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