14102120113 has 2 divisors, whose sum is σ = 14102120114. Its totient is φ = 14102120112.

The previous prime is 14102120107. The next prime is 14102120119. The reversal of 14102120113 is 31102120141.

It is a balanced prime because it is at equal distance from previous prime (14102120107) and next prime (14102120119).

It can be written as a sum of positive squares in only one way, i.e., 11614803984 + 2487316129 = 107772^2 + 49873^2 .

It is a cyclic number.

It is not a de Polignac number, because 14102120113 - 2¹³ = 14102111921 is a prime.

It is not a weakly prime, because it can be changed into another prime (14102120119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051060056 + 7051060057.

It is an arithmetic number, because the mean of its divisors is an integer number (7051060057).

Almost surely, 2^14102120113 is an apocalyptic number.

It is an amenable number.

14102120113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14102120113 is an equidigital number, since it uses as much as digits as its factorization.

14102120113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 14102120113 its reverse (31102120141), we get a palindrome (45204240254).

The spelling of 14102120113 in words is "fourteen billion, one hundred two million, one hundred twenty thousand, one hundred thirteen".