14102130053443 has 2 divisors, whose sum is σ = 14102130053444. Its totient is φ = 14102130053442.

The previous prime is 14102130053419. The next prime is 14102130053467. The reversal of 14102130053443 is 34435003120141.

14102130053443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (14102130053419) and next prime (14102130053467).

It is a cyclic number.

It is not a de Polignac number, because 14102130053443 - 2¹³ = 14102130045251 is a prime.

It is not a weakly prime, because it can be changed into another prime (14102130003443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051065026721 + 7051065026722.

It is an arithmetic number, because the mean of its divisors is an integer number (7051065026722).

Almost surely, 2^{14102130053443} is an apocalyptic number.

14102130053443 is a deficient number, since it is larger than the sum of its proper divisors (1).

14102130053443 is an equidigital number, since it uses as much as digits as its factorization.

14102130053443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 14102130053443 its reverse (34435003120141), we get a palindrome (48537133173584).

The spelling of 14102130053443 in words is "fourteen trillion, one hundred two billion, one hundred thirty million, fifty-three thousand, four hundred forty-three".