Base | Representation |
---|---|
bin | 10100100001010111111… |
… | …001110011000010000001 |
3 | 11222211000221022221121021 |
4 | 110201113321303002001 |
5 | 141101114323321423 |
6 | 2555503055225441 |
7 | 203612444402005 |
oct | 24412771630201 |
9 | 4884027287537 |
10 | 1410224042113 |
11 | 4a4088786477 |
12 | 1a9389218281 |
13 | a2ca2b48833 |
14 | 4c38040c705 |
15 | 26a3aa2595d |
hex | 14857e73081 |
1410224042113 has 2 divisors, whose sum is σ = 1410224042114. Its totient is φ = 1410224042112.
The previous prime is 1410224042083. The next prime is 1410224042203. The reversal of 1410224042113 is 3112404220141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 751605770304 + 658618271809 = 866952^2 + 811553^2 .
It is a cyclic number.
It is not a de Polignac number, because 1410224042113 - 213 = 1410224033921 is a prime.
It is not a weakly prime, because it can be changed into another prime (1410224046113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705112021056 + 705112021057.
It is an arithmetic number, because the mean of its divisors is an integer number (705112021057).
Almost surely, 21410224042113 is an apocalyptic number.
It is an amenable number.
1410224042113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1410224042113 is an equidigital number, since it uses as much as digits as its factorization.
1410224042113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 1410224042113 its reverse (3112404220141), we get a palindrome (4522628262254).
The spelling of 1410224042113 in words is "one trillion, four hundred ten billion, two hundred twenty-four million, forty-two thousand, one hundred thirteen".
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