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14103014325347 is a prime number
BaseRepresentation
bin1100110100111001110100…
…1010001011110001100011
31211221020100022112220000202
43031032131022023301203
53322030433131402342
645554500233335415
72653623561564443
oct315163512136143
954836308486022
1014103014325347
114548066a15a62
1216b9312b6756b
137b3ba70c244c
1436a837984123
15196cb9aab332
hexcd39d28bc63

14103014325347 has 2 divisors, whose sum is σ = 14103014325348. Its totient is φ = 14103014325346.

The previous prime is 14103014325343. The next prime is 14103014325467. The reversal of 14103014325347 is 74352341030141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14103014325347 - 22 = 14103014325343 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14103014325347.

It is not a weakly prime, because it can be changed into another prime (14103014325341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051507162673 + 7051507162674.

It is an arithmetic number, because the mean of its divisors is an integer number (7051507162674).

Almost surely, 214103014325347 is an apocalyptic number.

14103014325347 is a deficient number, since it is larger than the sum of its proper divisors (1).

14103014325347 is an equidigital number, since it uses as much as digits as its factorization.

14103014325347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120960, while the sum is 38.

Adding to 14103014325347 its reverse (74352341030141), we get a palindrome (88455355355488).

The spelling of 14103014325347 in words is "fourteen trillion, one hundred three billion, fourteen million, three hundred twenty-five thousand, three hundred forty-seven".