Base | Representation |
---|---|
bin | 1100110100111001110100… |
… | …1010001011110001100011 |
3 | 1211221020100022112220000202 |
4 | 3031032131022023301203 |
5 | 3322030433131402342 |
6 | 45554500233335415 |
7 | 2653623561564443 |
oct | 315163512136143 |
9 | 54836308486022 |
10 | 14103014325347 |
11 | 4548066a15a62 |
12 | 16b9312b6756b |
13 | 7b3ba70c244c |
14 | 36a837984123 |
15 | 196cb9aab332 |
hex | cd39d28bc63 |
14103014325347 has 2 divisors, whose sum is σ = 14103014325348. Its totient is φ = 14103014325346.
The previous prime is 14103014325343. The next prime is 14103014325467. The reversal of 14103014325347 is 74352341030141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14103014325347 - 22 = 14103014325343 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14103014325347.
It is not a weakly prime, because it can be changed into another prime (14103014325341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051507162673 + 7051507162674.
It is an arithmetic number, because the mean of its divisors is an integer number (7051507162674).
Almost surely, 214103014325347 is an apocalyptic number.
14103014325347 is a deficient number, since it is larger than the sum of its proper divisors (1).
14103014325347 is an equidigital number, since it uses as much as digits as its factorization.
14103014325347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120960, while the sum is 38.
Adding to 14103014325347 its reverse (74352341030141), we get a palindrome (88455355355488).
The spelling of 14103014325347 in words is "fourteen trillion, one hundred three billion, fourteen million, three hundred twenty-five thousand, three hundred forty-seven".
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