Base | Representation |
---|---|
bin | 1100110100111001111000… |
… | …1111001011010100001001 |
3 | 1211221020101120120202102121 |
4 | 3031032132033023110021 |
5 | 3322031002244131101 |
6 | 45554502121131241 |
7 | 2653624201402453 |
oct | 315163617132411 |
9 | 54836346522377 |
10 | 14103032411401 |
11 | 454807614930a |
12 | 16b9319029b21 |
13 | 7b3baaa8565b |
14 | 36a83a1312d3 |
15 | 196cbb4800a1 |
hex | cd39e3cb509 |
14103032411401 has 2 divisors, whose sum is σ = 14103032411402. Its totient is φ = 14103032411400.
The previous prime is 14103032411341. The next prime is 14103032411423. The reversal of 14103032411401 is 10411423030141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12317537833225 + 1785494578176 = 3509635^2 + 1336224^2 .
It is a cyclic number.
It is not a de Polignac number, because 14103032411401 - 213 = 14103032403209 is a prime.
It is not a weakly prime, because it can be changed into another prime (14103032441401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051516205700 + 7051516205701.
It is an arithmetic number, because the mean of its divisors is an integer number (7051516205701).
Almost surely, 214103032411401 is an apocalyptic number.
It is an amenable number.
14103032411401 is a deficient number, since it is larger than the sum of its proper divisors (1).
14103032411401 is an equidigital number, since it uses as much as digits as its factorization.
14103032411401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 14103032411401 its reverse (10411423030141), we get a palindrome (24514455441542).
The spelling of 14103032411401 in words is "fourteen trillion, one hundred three billion, thirty-two million, four hundred eleven thousand, four hundred one".
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