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14103250355531 is a prime number
BaseRepresentation
bin1100110100111010101100…
…1110100100010101001011
31211221020221202200110120102
43031032223032210111023
53322031424042334111
645554535504320015
72653632456034211
oct315165316442513
954836852613512
1014103250355531
114548178177a27
1216b937a01300b
137b3c13c8338c
1436a85b064cb1
15196cd068113b
hexcd3ab3a454b

14103250355531 has 2 divisors, whose sum is σ = 14103250355532. Its totient is φ = 14103250355530.

The previous prime is 14103250355503. The next prime is 14103250355723. The reversal of 14103250355531 is 13555305230141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14103250355531 - 222 = 14103246161227 is a prime.

It is a super-2 number, since 2×141032503555312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14103250355731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051625177765 + 7051625177766.

It is an arithmetic number, because the mean of its divisors is an integer number (7051625177766).

Almost surely, 214103250355531 is an apocalyptic number.

14103250355531 is a deficient number, since it is larger than the sum of its proper divisors (1).

14103250355531 is an equidigital number, since it uses as much as digits as its factorization.

14103250355531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135000, while the sum is 38.

Adding to 14103250355531 its reverse (13555305230141), we get a palindrome (27658555585672).

The spelling of 14103250355531 in words is "fourteen trillion, one hundred three billion, two hundred fifty million, three hundred fifty-five thousand, five hundred thirty-one".