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141034355213333 is a prime number
BaseRepresentation
bin100000000100010100011110…
…101001001100010000010101
3200111100202022201001121222212
4200010110132221030100111
5121441201324413311313
61215542142141003205
741464252540366661
oct4004243651142025
9614322281047885
10141034355213333
1140a3537483a42a
12139994a0253505
136090637452b2a
1426b81563598a1
151148961dba3a8
hex80451ea4c415

141034355213333 has 2 divisors, whose sum is σ = 141034355213334. Its totient is φ = 141034355213332.

The previous prime is 141034355213327. The next prime is 141034355213359. The reversal of 141034355213333 is 333312553430141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 135916005523204 + 5118349690129 = 11658302^2 + 2262377^2 .

It is a cyclic number.

It is not a de Polignac number, because 141034355213333 - 228 = 141034086777877 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141034355213383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70517177606666 + 70517177606667.

It is an arithmetic number, because the mean of its divisors is an integer number (70517177606667).

Almost surely, 2141034355213333 is an apocalyptic number.

It is an amenable number.

141034355213333 is a deficient number, since it is larger than the sum of its proper divisors (1).

141034355213333 is an equidigital number, since it uses as much as digits as its factorization.

141034355213333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 583200, while the sum is 41.

The spelling of 141034355213333 in words is "one hundred forty-one trillion, thirty-four billion, three hundred fifty-five million, two hundred thirteen thousand, three hundred thirty-three".