Base | Representation |
---|---|
bin | 11010010001010000… |
… | …11100001001111001 |
3 | 1100101220011010110202 |
4 | 31020220130021321 |
5 | 212340441300041 |
6 | 10251250051545 |
7 | 1006332311351 |
oct | 151050341171 |
9 | 40356133422 |
10 | 14103462521 |
11 | 5a88045155 |
12 | 2897279bb5 |
13 | 1439b956c5 |
14 | 97b129b61 |
15 | 57826da9b |
hex | 348a1c279 |
14103462521 has 2 divisors, whose sum is σ = 14103462522. Its totient is φ = 14103462520.
The previous prime is 14103462509. The next prime is 14103462523. The reversal of 14103462521 is 12526430141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13429333225 + 674129296 = 115885^2 + 25964^2 .
It is a cyclic number.
It is not a de Polignac number, because 14103462521 - 210 = 14103461497 is a prime.
Together with 14103462523, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14103462523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051731260 + 7051731261.
It is an arithmetic number, because the mean of its divisors is an integer number (7051731261).
Almost surely, 214103462521 is an apocalyptic number.
It is an amenable number.
14103462521 is a deficient number, since it is larger than the sum of its proper divisors (1).
14103462521 is an equidigital number, since it uses as much as digits as its factorization.
14103462521 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 14103462521 its reverse (12526430141), we get a palindrome (26629892662).
The spelling of 14103462521 in words is "fourteen billion, one hundred three million, four hundred sixty-two thousand, five hundred twenty-one".
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