Base | Representation |
---|---|
bin | 11010010001010110… |
… | …00011011011111111 |
3 | 1100101221102221101011 |
4 | 31020223003123333 |
5 | 212341130211321 |
6 | 10251312500051 |
7 | 1006341164113 |
oct | 151053033377 |
9 | 40357387334 |
10 | 14104147711 |
11 | 5a88472a25 |
12 | 289754a627 |
13 | 143a075544 |
14 | 97b267743 |
15 | 578356ae1 |
hex | 348ac36ff |
14104147711 has 2 divisors, whose sum is σ = 14104147712. Its totient is φ = 14104147710.
The previous prime is 14104147693. The next prime is 14104147763. The reversal of 14104147711 is 11774140141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14104147711 - 213 = 14104139519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14104147781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7052073855 + 7052073856.
It is an arithmetic number, because the mean of its divisors is an integer number (7052073856).
Almost surely, 214104147711 is an apocalyptic number.
14104147711 is a deficient number, since it is larger than the sum of its proper divisors (1).
14104147711 is an equidigital number, since it uses as much as digits as its factorization.
14104147711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3136, while the sum is 31.
Adding to 14104147711 its reverse (11774140141), we get a palindrome (25878287852).
The spelling of 14104147711 in words is "fourteen billion, one hundred four million, one hundred forty-seven thousand, seven hundred eleven".
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