Base | Representation |
---|---|
bin | 1100110100111110010100… |
… | …0010110001111101001110 |
3 | 1211221100110100212222210112 |
4 | 3031033211002301331032 |
5 | 3322040420402003032 |
6 | 45555220034440022 |
7 | 2653665504561305 |
oct | 315174502617516 |
9 | 54840410788715 |
10 | 14104220344142 |
11 | 4548625762805 |
12 | 16b95aaa33012 |
13 | 7b4039c13336 |
14 | 36a90dbdd43c |
15 | 196d3a8d51b2 |
hex | cd3e50b1f4e |
14104220344142 has 4 divisors (see below), whose sum is σ = 21156330516216. Its totient is φ = 7052110172070.
The previous prime is 14104220344139. The next prime is 14104220344147. The reversal of 14104220344142 is 24144302240141.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×141042203441423 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 14104220344099 and 14104220344108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14104220344147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3526055086034 + ... + 3526055086037.
It is an arithmetic number, because the mean of its divisors is an integer number (5289082629054).
Almost surely, 214104220344142 is an apocalyptic number.
14104220344142 is a deficient number, since it is larger than the sum of its proper divisors (7052110172074).
14104220344142 is an equidigital number, since it uses as much as digits as its factorization.
14104220344142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7052110172073.
The product of its (nonzero) digits is 24576, while the sum is 32.
Adding to 14104220344142 its reverse (24144302240141), we get a palindrome (38248522584283).
The spelling of 14104220344142 in words is "fourteen trillion, one hundred four billion, two hundred twenty million, three hundred forty-four thousand, one hundred forty-two".
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