14104362020233 has 2 divisors, whose sum is σ = 14104362020234. Its totient is φ = 14104362020232.

The previous prime is 14104362020197. The next prime is 14104362020237. The reversal of 14104362020233 is 33202026340141.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13070018101504 + 1034343918729 = 3615248^2 + 1017027^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14104362020233 is a prime.

It is a super-3 number, since 3×14104362020233³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 14104362020195 and 14104362020204.

It is not a weakly prime, because it can be changed into another prime (14104362020237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7052181010116 + 7052181010117.

It is an arithmetic number, because the mean of its divisors is an integer number (7052181010117).

Almost surely, 2^{14104362020233} is an apocalyptic number.

It is an amenable number.

14104362020233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14104362020233 is an equidigital number, since it uses as much as digits as its factorization.

14104362020233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 14104362020233 its reverse (33202026340141), we get a palindrome (47306388360374).

The spelling of 14104362020233 in words is "fourteen trillion, one hundred four billion, three hundred sixty-two million, twenty thousand, two hundred thirty-three".