14104404321433 has 2 divisors, whose sum is σ = 14104404321434. Its totient is φ = 14104404321432.

The previous prime is 14104404321401. The next prime is 14104404321479. The reversal of 14104404321433 is 33412340440141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11281994241424 + 2822410080009 = 3358868^2 + 1680003^2 .

It is a cyclic number.

It is not a de Polignac number, because 14104404321433 - 2⁵ = 14104404321401 is a prime.

It is not a weakly prime, because it can be changed into another prime (14104404321533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7052202160716 + 7052202160717.

It is an arithmetic number, because the mean of its divisors is an integer number (7052202160717).

Almost surely, 2^{14104404321433} is an apocalyptic number.

It is an amenable number.

14104404321433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14104404321433 is an equidigital number, since it uses as much as digits as its factorization.

14104404321433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55296, while the sum is 34.

Adding to 14104404321433 its reverse (33412340440141), we get a palindrome (47516744761574).

The spelling of 14104404321433 in words is "fourteen trillion, one hundred four billion, four hundred four million, three hundred twenty-one thousand, four hundred thirty-three".