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141044537 is a prime number
BaseRepresentation
bin10000110100000…
…10101100111001
3100211101210201202
420122002230321
5242101411122
621555023545
73331600364
oct1032025471
9324353652
10141044537
1172685937
123b29abb5
13232b490a
1414a370db
15c5b0e92
hex8682b39

141044537 has 2 divisors, whose sum is σ = 141044538. Its totient is φ = 141044536.

The previous prime is 141044507. The next prime is 141044569. The reversal of 141044537 is 735440141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 136866601 + 4177936 = 11699^2 + 2044^2 .

It is a cyclic number.

It is not a de Polignac number, because 141044537 - 218 = 140782393 is a prime.

It is a super-2 number, since 2×1410445372 = 39787122835088738, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (141044507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70522268 + 70522269.

It is an arithmetic number, because the mean of its divisors is an integer number (70522269).

Almost surely, 2141044537 is an apocalyptic number.

It is an amenable number.

141044537 is a deficient number, since it is larger than the sum of its proper divisors (1).

141044537 is an equidigital number, since it uses as much as digits as its factorization.

141044537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 29.

The square root of 141044537 is about 11876.2172849776. The cubic root of 141044537 is about 520.5375813787.

Adding to 141044537 its reverse (735440141), we get a palindrome (876484678).

The spelling of 141044537 in words is "one hundred forty-one million, forty-four thousand, five hundred thirty-seven".