1410523626131 has 2 divisors, whose sum is σ = 1410523626132. Its totient is φ = 1410523626130.

The previous prime is 1410523626121. The next prime is 1410523626133. The reversal of 1410523626131 is 1316263250141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1410523626131 - 2¹⁰ = 1410523625107 is a prime.

It is a super-2 number, since 2×1410523626131² (a number of 25 digits) contains 22 as substring.

Together with 1410523626133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1410523626091 and 1410523626100.

It is not a weakly prime, because it can be changed into another prime (1410523626133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705261813065 + 705261813066.

It is an arithmetic number, because the mean of its divisors is an integer number (705261813066).

Almost surely, 2^{1410523626131} is an apocalyptic number.

1410523626131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1410523626131 is an equidigital number, since it uses as much as digits as its factorization.

1410523626131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 1410523626131 its reverse (1316263250141), we get a palindrome (2726786876272).

The spelling of 1410523626131 in words is "one trillion, four hundred ten billion, five hundred twenty-three million, six hundred twenty-six thousand, one hundred thirty-one".