Base | Representation |
---|---|
bin | 100000000100100110001001… |
… | …101100100000110110111011 |
3 | 200111102120022011120100001102 |
4 | 200010212021230200312323 |
5 | 121442004210231143301 |
6 | 1215555001124242015 |
7 | 41465524016035526 |
oct | 4004461154406673 |
9 | 614376264510042 |
10 | 141053331115451 |
11 | 40a42422186567 |
12 | 139a10b724030b |
13 | 609236c903b91 |
14 | 26b903661dbbd |
15 | 11491c2c94b6b |
hex | 804989b20dbb |
141053331115451 has 2 divisors, whose sum is σ = 141053331115452. Its totient is φ = 141053331115450.
The previous prime is 141053331115439. The next prime is 141053331115531. The reversal of 141053331115451 is 154511133350141.
It is a weak prime.
It is an emirp because it is prime and its reverse (154511133350141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 141053331115451 - 230 = 141052257373627 is a prime.
It is not a weakly prime, because it can be changed into another prime (141053331115751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70526665557725 + 70526665557726.
It is an arithmetic number, because the mean of its divisors is an integer number (70526665557726).
Almost surely, 2141053331115451 is an apocalyptic number.
141053331115451 is a deficient number, since it is larger than the sum of its proper divisors (1).
141053331115451 is an equidigital number, since it uses as much as digits as its factorization.
141053331115451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54000, while the sum is 38.
Adding to 141053331115451 its reverse (154511133350141), we get a palindrome (295564464465592).
The spelling of 141053331115451 in words is "one hundred forty-one trillion, fifty-three billion, three hundred thirty-one million, one hundred fifteen thousand, four hundred fifty-one".
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