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141053331115451 is a prime number
BaseRepresentation
bin100000000100100110001001…
…101100100000110110111011
3200111102120022011120100001102
4200010212021230200312323
5121442004210231143301
61215555001124242015
741465524016035526
oct4004461154406673
9614376264510042
10141053331115451
1140a42422186567
12139a10b724030b
13609236c903b91
1426b903661dbbd
1511491c2c94b6b
hex804989b20dbb

141053331115451 has 2 divisors, whose sum is σ = 141053331115452. Its totient is φ = 141053331115450.

The previous prime is 141053331115439. The next prime is 141053331115531. The reversal of 141053331115451 is 154511133350141.

It is a weak prime.

It is an emirp because it is prime and its reverse (154511133350141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 141053331115451 - 230 = 141052257373627 is a prime.

It is not a weakly prime, because it can be changed into another prime (141053331115751) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70526665557725 + 70526665557726.

It is an arithmetic number, because the mean of its divisors is an integer number (70526665557726).

Almost surely, 2141053331115451 is an apocalyptic number.

141053331115451 is a deficient number, since it is larger than the sum of its proper divisors (1).

141053331115451 is an equidigital number, since it uses as much as digits as its factorization.

141053331115451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 38.

Adding to 141053331115451 its reverse (154511133350141), we get a palindrome (295564464465592).

The spelling of 141053331115451 in words is "one hundred forty-one trillion, fifty-three billion, three hundred thirty-one million, one hundred fifteen thousand, four hundred fifty-one".