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14105520213 = 34701840071
BaseRepresentation
bin11010010001100000…
…10010100001010101
31100102001000200002120
431020300102201111
5212342003121323
610251402130153
71006355641431
oct151060224125
940361020076
1014105520213
115a89220124
122897ab0959
13143a436185
1497b5039c1
155785285e3
hex348c12855

14105520213 has 4 divisors (see below), whose sum is σ = 18807360288. Its totient is φ = 9403680140.

The previous prime is 14105520173. The next prime is 14105520271. The reversal of 14105520213 is 31202550141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14105520213 - 229 = 13568649301 is a prime.

It is a super-3 number, since 3×141055202133 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14105520283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350920033 + ... + 2350920038.

It is an arithmetic number, because the mean of its divisors is an integer number (4701840072).

Almost surely, 214105520213 is an apocalyptic number.

It is an amenable number.

14105520213 is a deficient number, since it is larger than the sum of its proper divisors (4701840075).

14105520213 is an equidigital number, since it uses as much as digits as its factorization.

14105520213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4701840074.

The product of its (nonzero) digits is 1200, while the sum is 24.

The spelling of 14105520213 in words is "fourteen billion, one hundred five million, five hundred twenty thousand, two hundred thirteen".

Divisors: 1 3 4701840071 14105520213