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14106535131631 is a prime number
BaseRepresentation
bin1100110101000110111100…
…0000111111100111101111
31211221120102200120101021111
43031101233000333213233
53322110140443203011
650000241444412451
72654110043132005
oct315215700774757
954846380511244
1014106535131631
114549603363918
1216b9b360a7127
137b4318665187
1436aa8d3daa75
15196e23c28121
hexcd46f03f9ef

14106535131631 has 2 divisors, whose sum is σ = 14106535131632. Its totient is φ = 14106535131630.

The previous prime is 14106535131511. The next prime is 14106535131707. The reversal of 14106535131631 is 13613153560141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14106535131631 - 217 = 14106535000559 is a prime.

It is a super-2 number, since 2×141065351316312 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14106535135631) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7053267565815 + 7053267565816.

It is an arithmetic number, because the mean of its divisors is an integer number (7053267565816).

Almost surely, 214106535131631 is an apocalyptic number.

14106535131631 is a deficient number, since it is larger than the sum of its proper divisors (1).

14106535131631 is an equidigital number, since it uses as much as digits as its factorization.

14106535131631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 40.

Adding to 14106535131631 its reverse (13613153560141), we get a palindrome (27719688691772).

The spelling of 14106535131631 in words is "fourteen trillion, one hundred six billion, five hundred thirty-five million, one hundred thirty-one thousand, six hundred thirty-one".