Base | Representation |
---|---|
bin | 1100110101010011110110… |
… | …0110101111101100100101 |
3 | 1211221220101020110120012102 |
4 | 3031110331212233230211 |
5 | 3322134240242244443 |
6 | 50002013421101445 |
7 | 2654261660514164 |
oct | 315247546575445 |
9 | 54856336416172 |
10 | 14110001134373 |
11 | 455002187aaa1 |
12 | 16ba7429b7885 |
13 | 7b474b75a281 |
14 | 36acdb8693db |
15 | 19707816bcb8 |
hex | cd53d9afb25 |
14110001134373 has 2 divisors, whose sum is σ = 14110001134374. Its totient is φ = 14110001134372.
The previous prime is 14110001134363. The next prime is 14110001134391. The reversal of 14110001134373 is 37343110001141.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8580575864644 + 5529425269729 = 2929262^2 + 2351473^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14110001134373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14110001134343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055000567186 + 7055000567187.
It is an arithmetic number, because the mean of its divisors is an integer number (7055000567187).
Almost surely, 214110001134373 is an apocalyptic number.
It is an amenable number.
14110001134373 is a deficient number, since it is larger than the sum of its proper divisors (1).
14110001134373 is an equidigital number, since it uses as much as digits as its factorization.
14110001134373 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 29.
The spelling of 14110001134373 in words is "fourteen trillion, one hundred ten billion, one million, one hundred thirty-four thousand, three hundred seventy-three".
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