Base | Representation |
---|---|
bin | 11010010010000011… |
… | …00101100000100001 |
3 | 1100102100120000212122 |
4 | 31021001211200201 |
5 | 212344133220213 |
6 | 10252043234025 |
7 | 1006442324636 |
oct | 151101454041 |
9 | 40370500778 |
10 | 14110054433 |
11 | 5a90837812 |
12 | 2899518915 |
13 | 143b362c47 |
14 | 97bd6418d |
15 | 578b21d08 |
hex | 349065821 |
14110054433 has 2 divisors, whose sum is σ = 14110054434. Its totient is φ = 14110054432.
The previous prime is 14110054391. The next prime is 14110054447. The reversal of 14110054433 is 33445001141.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13794032704 + 316021729 = 117448^2 + 17777^2 .
It is a cyclic number.
It is not a de Polignac number, because 14110054433 - 226 = 14042945569 is a prime.
It is a super-2 number, since 2×141100544332 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (14110024433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055027216 + 7055027217.
It is an arithmetic number, because the mean of its divisors is an integer number (7055027217).
Almost surely, 214110054433 is an apocalyptic number.
It is an amenable number.
14110054433 is a deficient number, since it is larger than the sum of its proper divisors (1).
14110054433 is an equidigital number, since it uses as much as digits as its factorization.
14110054433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 14110054433 its reverse (33445001141), we get a palindrome (47555055574).
The spelling of 14110054433 in words is "fourteen billion, one hundred ten million, fifty-four thousand, four hundred thirty-three".
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