Base | Representation |
---|---|
bin | 1000001101101001000… |
… | …1111111000001000001 |
3 | 111111012120121121112012 |
4 | 2003122101333001001 |
5 | 4302433340213441 |
6 | 144453154142305 |
7 | 13123421366441 |
oct | 2033221770101 |
9 | 444176547465 |
10 | 141101101121 |
11 | 54927990772 |
12 | 2341a581995 |
13 | 103c8a39c16 |
14 | 6b87976121 |
15 | 3a0c7239eb |
hex | 20da47f041 |
141101101121 has 2 divisors, whose sum is σ = 141101101122. Its totient is φ = 141101101120.
The previous prime is 141101101103. The next prime is 141101101129. The reversal of 141101101121 is 121101101141.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73766560000 + 67334541121 = 271600^2 + 259489^2 .
It is a cyclic number.
It is not a de Polignac number, because 141101101121 - 234 = 123921231937 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 141101101096 and 141101101105.
It is not a weakly prime, because it can be changed into another prime (141101101129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70550550560 + 70550550561.
It is an arithmetic number, because the mean of its divisors is an integer number (70550550561).
Almost surely, 2141101101121 is an apocalyptic number.
It is an amenable number.
141101101121 is a deficient number, since it is larger than the sum of its proper divisors (1).
141101101121 is an equidigital number, since it uses as much as digits as its factorization.
141101101121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 141101101121 its reverse (121101101141), we get a palindrome (262202202262).
The spelling of 141101101121 in words is "one hundred forty-one billion, one hundred one million, one hundred one thousand, one hundred twenty-one".
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