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141101101153 is a prime number
BaseRepresentation
bin1000001101101001000…
…1111111000001100001
3111111012120121121120101
42003122101333001201
54302433340214103
6144453154142401
713123421366515
oct2033221770141
9444176547511
10141101101153
11549279907a1
122341a581a01
13103c8a39c3c
146b87976145
153a0c723a1d
hex20da47f061

141101101153 has 2 divisors, whose sum is σ = 141101101154. Its totient is φ = 141101101152.

The previous prime is 141101101139. The next prime is 141101101157. The reversal of 141101101153 is 351101101141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131553466209 + 9547634944 = 362703^2 + 97712^2 .

It is a cyclic number.

It is not a de Polignac number, because 141101101153 - 25 = 141101101121 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 141101101153.

It is not a weakly prime, because it can be changed into another prime (141101101157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70550550576 + 70550550577.

It is an arithmetic number, because the mean of its divisors is an integer number (70550550577).

Almost surely, 2141101101153 is an apocalyptic number.

It is an amenable number.

141101101153 is a deficient number, since it is larger than the sum of its proper divisors (1).

141101101153 is an equidigital number, since it uses as much as digits as its factorization.

141101101153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 19.

Adding to 141101101153 its reverse (351101101141), we get a palindrome (492202202294).

The spelling of 141101101153 in words is "one hundred forty-one billion, one hundred one million, one hundred one thousand, one hundred fifty-three".