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1411032013 is a prime number
BaseRepresentation
bin101010000011010…
…1010001111001101
310122100002212000221
41110012222033031
510342211011023
6352003151341
746652400646
oct12406521715
93570085027
101411032013
11664544266
12334675551
13196441cb1
14d55846cd
1583d2385d
hex541aa3cd

1411032013 has 2 divisors, whose sum is σ = 1411032014. Its totient is φ = 1411032012.

The previous prime is 1411032001. The next prime is 1411032019. The reversal of 1411032013 is 3102301141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 941139684 + 469892329 = 30678^2 + 21677^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411032013 - 25 = 1411031981 is a prime.

It is a super-2 number, since 2×14110320132 = 3982022683421664338, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411032019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705516006 + 705516007.

It is an arithmetic number, because the mean of its divisors is an integer number (705516007).

Almost surely, 21411032013 is an apocalyptic number.

It is an amenable number.

1411032013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411032013 is an equidigital number, since it uses as much as digits as its factorization.

1411032013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1411032013 is about 37563.7060605047. The cubic root of 1411032013 is about 1121.6196838352.

Adding to 1411032013 its reverse (3102301141), we get a palindrome (4513333154).

The spelling of 1411032013 in words is "one billion, four hundred eleven million, thirty-two thousand, thirteen".