14110346500631 has 2 divisors, whose sum is σ = 14110346500632. Its totient is φ = 14110346500630.

The previous prime is 14110346500597. The next prime is 14110346500639. The reversal of 14110346500631 is 13600564301141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14110346500631 - 2²² = 14110342306327 is a prime.

It is a super-2 number, since 2×14110346500631² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14110346500591 and 14110346500600.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14110346500639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055173250315 + 7055173250316.

It is an arithmetic number, because the mean of its divisors is an integer number (7055173250316).

Almost surely, 2^{14110346500631} is an apocalyptic number.

14110346500631 is a deficient number, since it is larger than the sum of its proper divisors (1).

14110346500631 is an equidigital number, since it uses as much as digits as its factorization.

14110346500631 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 35.

The spelling of 14110346500631 in words is "fourteen trillion, one hundred ten billion, three hundred forty-six million, five hundred thousand, six hundred thirty-one".