Base | Representation |
---|---|
bin | 10100100010001000100… |
… | …111000011011011100110 |
3 | 11222220010212222111010121 |
4 | 110202020213003123212 |
5 | 141104303022242014 |
6 | 3000120130112154 |
7 | 203641626256621 |
oct | 24421047033346 |
9 | 4886125874117 |
10 | 1411041212134 |
11 | 4a4467a843a4 |
12 | 1a9576a1b65a |
13 | a30a32309a8 |
14 | 4c41ab66db8 |
15 | 26a87640124 |
hex | 148889c36e6 |
1411041212134 has 8 divisors (see below), whose sum is σ = 2117584812240. Its totient is φ = 705179608056.
The previous prime is 1411041212083. The next prime is 1411041212179. The reversal of 1411041212134 is 4312121401141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 1411041212099 and 1411041212108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170493834 + ... + 170502109.
It is an arithmetic number, because the mean of its divisors is an integer number (264698101530).
Almost surely, 21411041212134 is an apocalyptic number.
1411041212134 is a deficient number, since it is larger than the sum of its proper divisors (706543600106).
1411041212134 is a wasteful number, since it uses less digits than its factorization.
1411041212134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 340998014.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 1411041212134 its reverse (4312121401141), we get a palindrome (5723162613275).
The spelling of 1411041212134 in words is "one trillion, four hundred eleven billion, forty-one million, two hundred twelve thousand, one hundred thirty-four".
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