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14111041890161 is a prime number
BaseRepresentation
bin1100110101010111101110…
…1000111010011101110001
31211222000001202211102202002
43031111323220322131301
53322143403210441121
650002305000103345
72654326526011466
oct315257350723561
954860052742662
1014111041890161
114550506300247
1216ba993464b55
137b4886266cb8
1436ad99b8566d
151970d96ede0b
hexcd57ba3a771

14111041890161 has 2 divisors, whose sum is σ = 14111041890162. Its totient is φ = 14111041890160.

The previous prime is 14111041890133. The next prime is 14111041890181. The reversal of 14111041890161 is 16109814011141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14005445488225 + 105596401936 = 3742385^2 + 324956^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14111041890161 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14111041890181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055520945080 + 7055520945081.

It is an arithmetic number, because the mean of its divisors is an integer number (7055520945081).

Almost surely, 214111041890161 is an apocalyptic number.

It is an amenable number.

14111041890161 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111041890161 is an equidigital number, since it uses as much as digits as its factorization.

14111041890161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 38.

The spelling of 14111041890161 in words is "fourteen trillion, one hundred eleven billion, forty-one million, eight hundred ninety thousand, one hundred sixty-one".