Base | Representation |
---|---|
bin | 1100110101010111101110… |
… | …1001011010011100001100 |
3 | 1211222000001210002002101212 |
4 | 3031111323221122130030 |
5 | 3322143403224134012 |
6 | 50002305002553552 |
7 | 2654326530065360 |
oct | 315257351323414 |
9 | 54860053062355 |
10 | 14111042021132 |
11 | 455050638a691 |
12 | 16ba9935088b8 |
13 | 7b48862b17b4 |
14 | 36ad99bbb2a0 |
15 | 1970d9727b22 |
hex | cd57ba5a70c |
14111042021132 has 96 divisors (see below), whose sum is σ = 28789711856640. Its totient is φ = 5926622296320.
The previous prime is 14111042021081. The next prime is 14111042021177. The reversal of 14111042021132 is 23112024011141.
It is a super-2 number, since 2×141110420211322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14111042021098 and 14111042021107.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 706495898 + ... + 706515870.
It is an arithmetic number, because the mean of its divisors is an integer number (299892831840).
Almost surely, 214111042021132 is an apocalyptic number.
It is an amenable number.
14111042021132 is an abundant number, since it is smaller than the sum of its proper divisors (14678669835508).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14111042021132 is a wasteful number, since it uses less digits than its factorization.
14111042021132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21351 (or 21349 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 14111042021132 its reverse (23112024011141), we get a palindrome (37223066032273).
The spelling of 14111042021132 in words is "fourteen trillion, one hundred eleven billion, forty-two million, twenty-one thousand, one hundred thirty-two".
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