Base | Representation |
---|---|
bin | 1100110101010111101110… |
… | …1001011010100010011101 |
3 | 1211222000001210002002221201 |
4 | 3031111323221122202131 |
5 | 3322143403224142113 |
6 | 50002305002555501 |
7 | 2654326530066502 |
oct | 315257351324235 |
9 | 54860053062851 |
10 | 14111042021533 |
11 | 455050638aa16 |
12 | 16ba993508b91 |
13 | 7b48862b1a32 |
14 | 36ad99bbb4a9 |
15 | 1970d9727cdd |
hex | cd57ba5a89d |
14111042021533 has 2 divisors, whose sum is σ = 14111042021534. Its totient is φ = 14111042021532.
The previous prime is 14111042021509. The next prime is 14111042021539. The reversal of 14111042021533 is 33512024011141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12518201143449 + 1592840878084 = 3538107^2 + 1262078^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14111042021533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14111042021539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055521010766 + 7055521010767.
It is an arithmetic number, because the mean of its divisors is an integer number (7055521010767).
Almost surely, 214111042021533 is an apocalyptic number.
It is an amenable number.
14111042021533 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111042021533 is an equidigital number, since it uses as much as digits as its factorization.
14111042021533 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 14111042021533 its reverse (33512024011141), we get a palindrome (47623066032674).
The spelling of 14111042021533 in words is "fourteen trillion, one hundred eleven billion, forty-two million, twenty-one thousand, five hundred thirty-three".
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