Base | Representation |
---|---|
bin | 110101110101… |
… | …000110001001 |
3 | 222112220210211 |
4 | 311311012021 |
5 | 12103023423 |
6 | 1222241121 |
7 | 230641162 |
oct | 65650611 |
9 | 28486724 |
10 | 14111113 |
11 | 7a68985 |
12 | 48861a1 |
13 | 2c00b93 |
14 | 1c34769 |
15 | 138b10d |
hex | d75189 |
14111113 has 2 divisors, whose sum is σ = 14111114. Its totient is φ = 14111112.
The previous prime is 14111087. The next prime is 14111131. The reversal of 14111113 is 31111141.
It is a happy number.
14111113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
Together with next prime (14111131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13630864 + 480249 = 3692^2 + 693^2 .
It is an emirp because it is prime and its reverse (31111141) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14111113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14111093 and 14111102.
It is not a weakly prime, because it can be changed into another prime (14111143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055556 + 7055557.
It is an arithmetic number, because the mean of its divisors is an integer number (7055557).
Almost surely, 214111113 is an apocalyptic number.
It is an amenable number.
14111113 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111113 is an equidigital number, since it uses as much as digits as its factorization.
14111113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12, while the sum is 13.
The square root of 14111113 is about 3756.4761412792. The cubic root of 14111113 is about 241.6501615891.
Adding to 14111113 its reverse (31111141), we get a palindrome (45222254).
It can be divided in two parts, 1 and 4111113, that added together give a palindrome (4111114).
The spelling of 14111113 in words is "fourteen million, one hundred eleven thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •