Base | Representation |
---|---|
bin | 100000000101011011111111… |
… | …000011100111001111000011 |
3 | 200111122002111121011122210121 |
4 | 200011123333003213033003 |
5 | 121443431100434230003 |
6 | 1220041321011241111 |
7 | 41502641315161405 |
oct | 4005337703471703 |
9 | 614562447148717 |
10 | 141111134680003 |
11 | 40a64994849114 |
12 | 139b03495a9197 |
13 | 60979522aa007 |
14 | 26bbb5b4c2b75 |
15 | 114a957781cbd |
hex | 8056ff0e73c3 |
141111134680003 has 2 divisors, whose sum is σ = 141111134680004. Its totient is φ = 141111134680002.
The previous prime is 141111134679989. The next prime is 141111134680051. The reversal of 141111134680003 is 300086431111141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141111134680003 - 25 = 141111134679971 is a prime.
It is not a weakly prime, because it can be changed into another prime (141111134680903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70555567340001 + 70555567340002.
It is an arithmetic number, because the mean of its divisors is an integer number (70555567340002).
Almost surely, 2141111134680003 is an apocalyptic number.
141111134680003 is a deficient number, since it is larger than the sum of its proper divisors (1).
141111134680003 is an equidigital number, since it uses as much as digits as its factorization.
141111134680003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 34.
Adding to 141111134680003 its reverse (300086431111141), we get a palindrome (441197565791144).
The spelling of 141111134680003 in words is "one hundred forty-one trillion, one hundred eleven billion, one hundred thirty-four million, six hundred eighty thousand, three".
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