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14111125310 = 251411112531
BaseRepresentation
bin11010010010001011…
…01010111100111110
31100102102120102211202
431021011222330332
5212344422002220
610252122215502
71006454405012
oct151105527476
940372512752
1014111125310
115a913a9337
122899954592
13143b6494b9
1497c162542
15578c84275
hex34916af3e

14111125310 has 8 divisors (see below), whose sum is σ = 25400025576. Its totient is φ = 5644450120.

The previous prime is 14111125279. The next prime is 14111125313. The reversal of 14111125310 is 1352111141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×141111253102 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14111125313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 705556256 + ... + 705556275.

It is an arithmetic number, because the mean of its divisors is an integer number (3175003197).

Almost surely, 214111125310 is an apocalyptic number.

14111125310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14111125310 is a deficient number, since it is larger than the sum of its proper divisors (11288900266).

14111125310 is a wasteful number, since it uses less digits than its factorization.

14111125310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1411112538.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 14111125310 its reverse (1352111141), we get a palindrome (15463236451).

The spelling of 14111125310 in words is "fourteen billion, one hundred eleven million, one hundred twenty-five thousand, three hundred ten".

Divisors: 1 2 5 10 1411112531 2822225062 7055562655 14111125310