Base | Representation |
---|---|
bin | 100000000101011100000110… |
… | …001010111001101100000011 |
3 | 200111122002210220202022201212 |
4 | 200011130012022321230003 |
5 | 121443431322012443412 |
6 | 1220041340513320335 |
7 | 41502644264510663 |
oct | 4005340612715403 |
9 | 614562726668655 |
10 | 141111254031107 |
11 | 40a64a46157398 |
12 | 139b03815660ab |
13 | 6097970c37779 |
14 | 26bbb6d2b01a3 |
15 | 114a962eaa222 |
hex | 8057062b9b03 |
141111254031107 has 2 divisors, whose sum is σ = 141111254031108. Its totient is φ = 141111254031106.
The previous prime is 141111254031091. The next prime is 141111254031179. The reversal of 141111254031107 is 701130452111141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141111254031107 - 24 = 141111254031091 is a prime.
It is a super-2 number, since 2×1411112540311072 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (141111254033107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70555627015553 + 70555627015554.
It is an arithmetic number, because the mean of its divisors is an integer number (70555627015554).
Almost surely, 2141111254031107 is an apocalyptic number.
141111254031107 is a deficient number, since it is larger than the sum of its proper divisors (1).
141111254031107 is an equidigital number, since it uses as much as digits as its factorization.
141111254031107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3360, while the sum is 32.
The spelling of 141111254031107 in words is "one hundred forty-one trillion, one hundred eleven billion, two hundred fifty-four million, thirty-one thousand, one hundred seven".
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