Base | Representation |
---|---|
bin | 1100110101011000000110… |
… | …1011011011110100000011 |
3 | 1211222000022211111020101102 |
4 | 3031112001223123310003 |
5 | 3322144110130324324 |
6 | 50002323015525015 |
7 | 2654332166160323 |
oct | 315260153336403 |
9 | 54860284436342 |
10 | 14111143214339 |
11 | 4550558516636 |
12 | 16baa0138976b |
13 | 7b48a1252432 |
14 | 36ada93dd283 |
15 | 1970e3565dae |
hex | cd581adbd03 |
14111143214339 has 2 divisors, whose sum is σ = 14111143214340. Its totient is φ = 14111143214338.
The previous prime is 14111143214281. The next prime is 14111143214347. The reversal of 14111143214339 is 93341234111141.
14111143214339 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14111143214339 - 216 = 14111143148803 is a prime.
It is a super-3 number, since 3×141111432143393 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (14111143214359) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055571607169 + 7055571607170.
It is an arithmetic number, because the mean of its divisors is an integer number (7055571607170).
Almost surely, 214111143214339 is an apocalyptic number.
14111143214339 is a deficient number, since it is larger than the sum of its proper divisors (1).
14111143214339 is an equidigital number, since it uses as much as digits as its factorization.
14111143214339 is an evil number, because the sum of its binary digits is even.
The product of its digits is 31104, while the sum is 38.
The spelling of 14111143214339 in words is "fourteen trillion, one hundred eleven billion, one hundred forty-three million, two hundred fourteen thousand, three hundred thirty-nine".
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