14111231133130 has 16 divisors (see below), whose sum is σ = 25401193551720. Its totient is φ = 5644275228352.

The previous prime is 14111231133091. The next prime is 14111231133157. The reversal of 14111231133130 is 3133113211141.

It can be written as a sum of positive squares in 4 ways, for example, as 10328015520729 + 3783215612401 = 3213723^2 + 1945049^2 .

It is a junction number, because it is equal to n+sod(n) for n = 14111231133095 and 14111231133104.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 26880145 + ... + 27400084.

Almost surely, 2^{14111231133130} is an apocalyptic number.

14111231133130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14111231133130 is a deficient number, since it is larger than the sum of its proper divisors (11289962418590).

14111231133130 is a wasteful number, since it uses less digits than its factorization.

14111231133130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54306233.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 14111231133130 its reverse (3133113211141), we get a palindrome (17244344344271).

The spelling of 14111231133130 in words is "fourteen trillion, one hundred eleven billion, two hundred thirty-one million, one hundred thirty-three thousand, one hundred thirty".