141113100001 has 4 divisors (see below), whose sum is σ = 144115506432. Its totient is φ = 138110693572.

The previous prime is 141113099987. The next prime is 141113100103. The reversal of 141113100001 is 100001311141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 141113100001 - 2¹¹ = 141113097953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141113100701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1501203145 + ... + 1501203238.

It is an arithmetic number, because the mean of its divisors is an integer number (36028876608).

Almost surely, 2^141113100001 is an apocalyptic number.

It is an amenable number.

141113100001 is a deficient number, since it is larger than the sum of its proper divisors (3002406431).

141113100001 is an equidigital number, since it uses as much as digits as its factorization.

141113100001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3002406430.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 141113100001 its reverse (100001311141), we get a palindrome (241114411142).

The spelling of 141113100001 in words is "one hundred forty-one billion, one hundred thirteen million, one hundred thousand, one".